Question

Jika 8log6=p, maka 27log16 adalah

Answer 1

8log 6 = p
8log (2x3) = p
8log 2 + 8log 3 = p
2^3log 2 + 2^3log 3 = p
1/3 2log 2 + 1/3 2log 3 = p
1/3 + 1/3 2log 3 = p
1/3 2log 3 = (3p-1)/3
2log 3 = 3p - 1
3log 2 = 1/(3p -1)

27log 16
= 27log (8x2)
= 27log 8 + 27log 2
= 3^3log 2^3 + 3^3log 2
= 3log 2 + 1/3 3log 2
= 1/(3p-1) + 1/3 . 1/(3p-1)
= 4/(9p-3)

daritadi dapatnya segini, kalau kurang puas dilaporkan aja jawabannya :) .