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2log5 = b
6log2 x 2log5 = 6log5 = ab
a. 12log10 = 5log10/5log12 = 5log2 + 5log5/5log2 + 5log6 = (1/b + 1) : (1/b + 1/ab) = ((b+1)/b) : ((a+1)/ab) = ((b+1)/b) x (ab/(a+1)) = (ab+a)/(a+1)
b. 36log25 = 6^2log5^2 = 2/2 x 6log5 = ab
c. 5log72 = 5log36 + 5log2 = 2 x 5log6 + 5log2 = 2/ab + 1/b = (2+a)/ab