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Verified answer
Jawab⁴log 6 = m + 1
⁴lo g 2 + ⁴log 3 = m + 1
²^²log 2 + ²^²log 3 = m + 1
1/2 (²log 2 + ²log 3) = m + 1
²log 2 + ²log 3 = 2m + 2
1 + ²log 3 = 2m + 2
²log 3 = 2m + 2 - 1
²log 3 = 2m + 1
⁹log 8 = ³^²log 2³ = 3/2 . (³log 2)
= 3/2 ( 1/ (2m+1)
= 3 / 2(2m+1)
= 3 / (4m + 2)