Jika 3sinx + 4cosy = 5, maka nilai minimum 3cosx + 4 siny adalah …
Juang
(3 sinx+4 cosy)^2+(3 cosx+4 siny)^2=9+16+24 sin(x+y)=25+24 sin(x+y) So,Minimum value of (3 cosx+4 sin y)=(25-25+(24×0))^(1/2)=0
3 votes
Thanks 1
More Questions From This User See All