Jika 3log7=p dan 5log3=q maka 21log525=?.... Question from @jihad99

IcukSugiarto $~^{21}log\ 525\\\boxed{= \frac{~^{3}log\ 525}{~^{3}log\ 21} }\\\\\boxed{= \frac{~^{3}log\ (3 \times 7 \times 25)}{~^{3}log\ (3 \times 7)} }\\\\\boxed{= \frac{~^{3}log\ 3 +~^{3}log\ 7 +~^{3}log\ 25}{~^{3}log\ 3 +~^{3}log\ 7}}\\\\\boxed{= \frac{~^{3}log\ 3 +~^{3}log\ 7 +~^{3}log\ 5^{2}}{~^{3}log\ 3 +~^{3}log\ 7}}\\\\\boxed{= \frac{~^{3}log\ 3 +~^{3}log\ 7 +2~^{3}log\ 5}{~^{3}log\ 3 +~^{3}log\ 7}}\\\\\boxed{= \frac{1 +p +2( \frac{1}{q} )}{1 +p}}~~~~~\Rightarrow~~[ingat\ ~^{3}log\ 5 = \frac{1}{^{5}log\ 3}]$
$\boxed{= \frac{1 +p +\frac{2}{q}}{1 +p}}}\\\\\boxed{= \frac{1 +p +\frac{2}{q}}{1 +p}\times \frac{q}{q} }}\\\\\boxed{= \frac{q +pq +2}{q +pq}}}$

$======================================\\\underline{\bold{Note:}}\\\\remember\ this\ formula:\\1]\boxed{~^{a}log\ (b \times c)=~^{a}log\ b+~^{a}log\ c}\\\\2]\boxed{~^{a}log\ b= \frac{1}{~^{b}log\ a} }\\\\3]\boxed{~^{a}log\ a = 1}\\\\4]\boxed{~^{a}log\ b^{m}=m~^{a}log\ b}$

2 votes Thanks 4

jihad99 nice friend.... i know it just need to be patience.... right?

IcukSugiarto of course

jihad99 anyway..... thanks, thats mean a lot of me

IcukSugiarto you're welcome :)

QuizBrainly $^{21}log\ 525\\\\= \frac{log\ 525}{log\ 21}\\\\= \frac{^{3}log\ 525}{^{3}log\ 21}\\\\= \frac{^{3}log\ (3 \times 7 \times 5^{2})}{^{3}log\ (3 \times 7)}\\\\= \frac{~^{3}log\ 3 +~^{3}log\ 7+2~^{3}log\ 5}{~^{3}log\ 3+~^{3}log\ 7}\\\\= \frac{1 +p+2/q}{1+p}\\\\= \frac{1 +p+2/q}{1+p} \times \frac{q}{q} \\\\= \frac{q +pq+2}{q+pq}$

0 votes Thanks 3

jihad99 terima kasih

QuizBrainly sama-sama

Sebutkan dan jelaskan jenis jenis kalimat tunggal....

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