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Verified answer
Cos 2x = y3 y² + 4 y - 4 = 0
(3y- 2)(y+2) = 0
y = 2/3 ∨ y= -2
cos 2x = 2/3 ∨ cos 2x = -2 (Tidak Memenuhi, krn -1≤ cos ax ≤ 1
cos 2x = 2/3
2cos² x - 1 = 2/3
2 cos² x = 1 + 2/3 = 5/3
cos² x = 5/6
cos x = +_ √(5/6)
cos x = +- 1/6 √30