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log3 = a.log2
log7/log3 = b
log7 =b.log3 = a.b.log2
log56/log14 = log (2³.7)/log (2.7)
log2 + log2 + log2 + a.b.log2/log2 + a.b.log2 = log2(1+1+1+ab)/log2(1+ab)
log 2nya sama sama dicoret
berarti tinggal 3+ab/1+ab