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maka ²log3 x ³log5 = ab, artinya ²log5 = ab
dg demikian nilai dari :
25' log 36
= 5² ' log 6²
= 5' log 6
= 5' log 2 + 5' log 3
= 1/(²log5) + 1/(³log5)
= 1/ab + 1/b
= 1/ab + a/ab
= (1 + a)/(ab)
=³log6/³log5=(1/²log3+³log3)/b=(1/a+1)/b⇒
=kita rapikan soal menjadi=(1+a)/ab