kan 2log5=ab,
2log3+2log5/2log2=a+ab/1=a+ab
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kan 2log5=ab,
2log3+2log5/2log2=a+ab/1=a+ab
²log15 = ³log15/ ³log2 = ³log5.3/ 1/²log3 = ³log5 + ³log3/ 1/²log3 = b+1/1/a = a(b+1) = ab +a