Question

Jika 16log5=p, maka 20log320 adalah

Answer 1

16log5=p

20log320=?? 20log(20x16) = 20log20 + 20log16

= 1  +  1/(16log20) = 1+1 / (16 log 4 + 16log5)

=1 + 1/(16log16^(1/2)  + p)

= 1+1/(1/2+p)

1+ 1/(1+2p)/2  =  1+ 2/(1+2p)= 1+2p+2)/(1+2p)=(3+2p)/(1+2p)

Answer 2

⁵log 16 = 1/p
⁵log 2 = 1/4p
²⁰log 320 = ²⁰log (2⁶ * 5) = 6 * ²⁰log 2 + ²⁰log 5 = 6/(4p+2) + 4p/(4p+2) = (4p+6)/(4p+2)