Respuesta:
[tex]S= 2[/tex] ✔️
Explicación paso a paso:
[tex]\boldsymbol{Si:}[/tex]
[tex]tan60 = \frac{CO}{CA}[/tex]
[tex]CO = Cateto Opuesto = k\sqrt{3}[/tex]
[tex]CA= Cateto Adyacente = k[/tex]
[tex]tan60 = \frac{k\sqrt{3} }{k} = \sqrt{3}[/tex]
[tex]\boldsymbol{Entonces:}[/tex]
[tex]tan^{2} 60 - 1[/tex]
[tex](\sqrt{3} )^{2} - 1[/tex]
[tex]3 - 1[/tex]
[tex]\boxed{\bf{2}}[/tex] ✔️
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Respuesta:
[tex]S= 2[/tex] ✔️
Explicación paso a paso:
[tex]\boldsymbol{Si:}[/tex]
[tex]tan60 = \frac{CO}{CA}[/tex]
[tex]CO = Cateto Opuesto = k\sqrt{3}[/tex]
[tex]CA= Cateto Adyacente = k[/tex]
[tex]tan60 = \frac{k\sqrt{3} }{k} = \sqrt{3}[/tex]
[tex]\boldsymbol{Entonces:}[/tex]
[tex]tan^{2} 60 - 1[/tex]
[tex](\sqrt{3} )^{2} - 1[/tex]
[tex]3 - 1[/tex]
[tex]\boxed{\bf{2}}[/tex] ✔️