Odpowiedź:
[tex]\huge\boxed{a) \ Zmaleje \ 25 \ razy}[/tex]
Wyjaśnienie:
Korzystamy z prawa Coulomba:
[tex]F = k\cdot\frac{q_1\cdot q_2}{r^{2}}\\\\\\F_1 = k\cdot\frac{q_1\cdot q_2}{3^{2}} = k\cdot\frac{q_1\cdot q_2}{9} = \frac{1}{9}\cdot k\cdot q_1q_2\\\\F_2 = k\cdot \frac{q_1\cdot q_2}{r^{2}} = k\cdot\frac{q_1\cdot q_2}{15^{2}} = k\cdot\frac{q_1\cdot q_2}{225} = \frac{1}{25}\cdot k\cdot q_1q_2[/tex]
[tex]\frac{F_1}{F_2} = \frac{\frac{1}{9}}{\frac{1}{225}} = \frac{225}{9} = 25\\\\\boxed{F_2 = \frac{1}{25}F_1}[/tex]
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Odpowiedź:
[tex]\huge\boxed{a) \ Zmaleje \ 25 \ razy}[/tex]
Wyjaśnienie:
Korzystamy z prawa Coulomba:
[tex]F = k\cdot\frac{q_1\cdot q_2}{r^{2}}\\\\\\F_1 = k\cdot\frac{q_1\cdot q_2}{3^{2}} = k\cdot\frac{q_1\cdot q_2}{9} = \frac{1}{9}\cdot k\cdot q_1q_2\\\\F_2 = k\cdot \frac{q_1\cdot q_2}{r^{2}} = k\cdot\frac{q_1\cdot q_2}{15^{2}} = k\cdot\frac{q_1\cdot q_2}{225} = \frac{1}{25}\cdot k\cdot q_1q_2[/tex]
[tex]\frac{F_1}{F_2} = \frac{\frac{1}{9}}{\frac{1}{225}} = \frac{225}{9} = 25\\\\\boxed{F_2 = \frac{1}{25}F_1}[/tex]