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f(-1)=-1a+b=2
f(2)=2a+b=11
keduanya dijadikan persamaan terus dikurangi
-3a=-9
a=-9/-3
a=3
2a+b=11
2(3)+b=11
6+b=11
b=11-6
b=5
jadi= f(x)=ax+b
f(x)=3a+5