Jawaban:
Jawaban【Answer】: c. 2
【Explanation】:
1. We are given two functions: \(f(x) = \frac{2x}{3-x}\) and the inverse of another function \(g^{-1}(x) = \frac{6}{2+x}\).
2. To find \((g \circ f)^{-1}(1)\), we first need to determine the function \(g(x)\) by inverting \(g^{-1}(x)\).
3. Once we have both \(f(x)\) and \(g(x)\), we can find the composition \(g \circ f(x)\).
4. Finally, we find the inverse of the composition and evaluate it at \(x = 1\).
5. The result is \(2\), which corresponds to option c.
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Jawaban:
Jawaban【Answer】: c. 2
【Explanation】:
1. We are given two functions: \(f(x) = \frac{2x}{3-x}\) and the inverse of another function \(g^{-1}(x) = \frac{6}{2+x}\).
2. To find \((g \circ f)^{-1}(1)\), we first need to determine the function \(g(x)\) by inverting \(g^{-1}(x)\).
3. Once we have both \(f(x)\) and \(g(x)\), we can find the composition \(g \circ f(x)\).
4. Finally, we find the inverse of the composition and evaluate it at \(x = 1\).
5. The result is \(2\), which corresponds to option c.