1/Rp = 1/R1 + 1/R2
1/Rp = 1/10 + 1/10
1/Rp = 2+10
Rp = 10/2
Rp = 5 Ω
→ R total = 5 + 4 + 1 = 10 Ω
→ Ԑ = 40 Volt
I = V/R total
I = 40/10
I = 4 Ampere
Jadi, besar kuat arus pada amperemeter adalah
= D. 4,0 A
Jangan lupa jadikan jawaban terbaik, semoga membantu.
Semangat Belajar!!
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1/Rp = 1/R1 + 1/R2
1/Rp = 1/10 + 1/10
1/Rp = 2+10
Rp = 10/2
Rp = 5 Ω
→ R total = 5 + 4 + 1 = 10 Ω
→ Ԑ = 40 Volt
I = V/R total
I = 40/10
I = 4 Ampere
Jadi, besar kuat arus pada amperemeter adalah
= D. 4,0 A
Jangan lupa jadikan jawaban terbaik, semoga membantu.
Semangat Belajar!!