Lenysaputra
3. v setengah bola = 1/2 x 4/3 x 22/7 x 21 x 21 x 21 = 19.404 v tabung = 22/7 x 21 x 21 x 21 = 29.106 v kerucut = 1/3 x 22/7 x 21 x 21 x 21 x 30 = 13.860 v total = 62.370 cm³ 4. L selimut kerucut = π r s ( s = √(21²) + (28²) = √1225 = 35 = 22/7 x 21 x 35 =1386 L selimut tabung = 2 π r t = 2. 22/7. 21. 21 = 2772 1/2 luas bola = 1/2 . 4 . π. r² = 2772 total = 6930 cm²
v tabung = 22/7 x 21 x 21 x 21 = 29.106
v kerucut = 1/3 x 22/7 x 21 x 21 x 21 x 30 = 13.860
v total = 62.370 cm³
4. L selimut kerucut = π r s ( s = √(21²) + (28²) = √1225 = 35
= 22/7 x 21 x 35 =1386
L selimut tabung = 2 π r t = 2. 22/7. 21. 21 = 2772
1/2 luas bola = 1/2 . 4 . π. r² = 2772
total = 6930 cm²