Question

jawaban dengan logika​

Answer 1

[tex] \frac{x - 2}{x} \geqslant \frac{x + 1}{x + 3} \\ [/tex]

Penyelesaian :

[tex] = \frac{x - 2}{x} - \frac{x + 1}{x + 3} \geqslant 0 \\ [/tex]

[tex] = \frac{(x - 2)(x + 3) - (x + 1) \times x}{x(x + 3)} \geqslant 0 \\ [/tex]

= ((x - 2) (x + 3)-(x + 1).x). x(x + 3) ≥ 0

= (x - 2) (x + 3) - (x + 1).x = 0 atau x + 3 = 0

no solution atau x = -3

x = 0 atau x = -3

x1 = -3

x2 = 0

makaa :

-3 ≤ x ≤ 0