[tex] \sin(240) = \sin(180 + 60) \: \: \: \: \: \: \: \: \: \: \\ = - \sin(60) \\ = - \frac{1}{2} \sqrt{3} \\ \\ \tan(300) = \tan(360 - \alpha ) = - \tan\alpha \\ = \tan(360 - 60 \\ = - \tan(60) \\ = - \sqrt{3} \\ \\ = \sin(240) + \tan(300) \\ = - \frac{1}{2} \sqrt{3} + - \sqrt{3}\\ = - \frac{3}{2} \sqrt{3} [/tex]
maka, jawaban yang benar adalah A.
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[tex] \sin(240) = \sin(180 + 60) \: \: \: \: \: \: \: \: \: \: \\ = - \sin(60) \\ = - \frac{1}{2} \sqrt{3} \\ \\ \tan(300) = \tan(360 - \alpha ) = - \tan\alpha \\ = \tan(360 - 60 \\ = - \tan(60) \\ = - \sqrt{3} \\ \\ = \sin(240) + \tan(300) \\ = - \frac{1}{2} \sqrt{3} + - \sqrt{3}\\ = - \frac{3}{2} \sqrt{3} [/tex]
maka, jawaban yang benar adalah A.