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L = 5s² + 4 a.t / 2
= 5 . 18² + 2 . 18 . 12
= 5 . 324 + 432
= 1620 + 432
= 2052 cm²
= 1/2 x 18
= 9
tinggi segitiga tegaknya
Luas permukaan kubus tampa alas dan tutup
Lp = 4 x s²
= 4 x 18 x 18
= 1296 cm²
luas limas
Lp = La + ( 4 x a x t)
= 324 + ( 4x9x12)
= 324 + 432
= 756 cm²
jawabannya 756 cm²