Question

jawab yang bener yaaaa !​

Answer 1

Materi : Bilangan Berakar

1. (5√3 × 2√2) + 3√6 - √150

10√6 + 3√6 - √(25 × 6)

13√6 - 5√6

7√6

2. Akar kali akar, akarnya hilang

[tex] \frac{9 \sqrt{27}}{3 \sqrt{3} } + ( \sqrt{ 32} \times \sqrt{2} ) \\ \frac{9 \sqrt{9 \times 3} }{3 \sqrt{3} } + (\sqrt{16 \times 2} \times \sqrt{2} ) \\ \frac{9 \times 3 \sqrt{3} }{3 \sqrt{ 3} } + (4 \sqrt{2} \times \sqrt{2} ) \\ \frac{27 \sqrt{ 3} }{3 \sqrt{3} } + (4 \times 2) \\ 9 + 8 \\ = 17[/tex]

3. Ada merasionalkan

[tex](4 \sqrt{2} \times 5 \sqrt{5} ) - ( \frac{12 \sqrt{20} }{6 \sqrt{2} } ) \\ 20 \sqrt{10} - ( \frac{12 \sqrt{4 \times 5} }{6 \sqrt{2} } ) \\ 20 \sqrt{10} - ( \frac{12 \times 2 \sqrt{5} }{6 \sqrt{2} } ) \\ 20 \sqrt{10} - \frac{24 \sqrt{5} }{6 \sqrt{2} } \\ 20 \sqrt{10} - \frac{4 \sqrt{5} }{ \sqrt{2} } \\ 20 \sqrt{10} - \frac{4 \sqrt{5} }{ \sqrt{2} } \times \frac{ \sqrt{2} }{ \sqrt{2} } \\ 20 \sqrt{10} - \frac{4 \sqrt{10} }{2} \\ 20 \sqrt{10} - 2 \sqrt{10} \\ 18 \sqrt{10} [/tex]

4. Pembagian akar sama seperti pembagian biasa

[tex] \frac{18 \sqrt{14} }{9 \sqrt{2} } + \sqrt{63} - 2 \sqrt{7} \\ 2 \sqrt{7} + \sqrt{9 \times 7} - 2 \sqrt{7} \\ 2 \sqrt{7} + 3 \sqrt{7} - 2 \sqrt{7} \\ 3 \sqrt{7} [/tex]

5. 5√3 (2√5 + 3√3)

(5√3 × 2√5) + (5√3 × 3√3)

10√15 + 15 × 3

10√15 + 45

45 + 10√15

Semoga bermanfaat