Question

Jawab ya yg baikkkkk
pleasee

Answer 1

Luas bidang 1 (setengah lingkaran)
= 1/2 x 22/7 x 7 x 7 = 77 cm2

Luas bisang 2 (persegi panjang)
= p x l = 9 x 14 = 126 cm2

Luas bidang 3 (segitiga siku2)

Luas segitiga = alas x tinggi /2 = 7 x 14 /2 = 49 cm2

Maka luas bangunan = 49 + 126 + 77 = 252 cm2

Answer 2

L 1/2 lingkaran = 1/2 × πr²
= 1/2 × 22/7 × 7 × 7
= 77 cm²
L persegi panjang = p × l
= 14 × 9
= 126 cm²
L segitiga = 1/2 × a × t
= 1/2 × 7 × 14
= 49cm²
L total = 252 cm² (A)