Jawab ya :-(
Lensa cembung berjari jari 30 cm dan perbesaran bayangan 2 kali,maka jarak benda adalah...??
Lensa cembung berjari jari 30 cm dan perbesaran bayangan 2 kali,maka jarak benda adalah...??
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R = 30 cm = 2f
Dit : So?
Jawab :
-> 2f = 30
f = 15 cm
-> M = f/ So - f
2 = 15/So-15
2 . So - 30 = 15
2 So = 15 + 30
2 So = 45
So = 45/2= 22,5 cm