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Verified answer
(3a)FEH = FGH = 54,8 derajat
FGE = 54,8 : 2 = 27,4 derajat
EFG = EHG = 180 - 54,8 = 125,2 derajat
EHF = 125,2 : 2 = 62,6 derajat
(3b)
luas segitiga EFG
= segitga besar - segitiga kecil
= [1/2 x (8 + 4,6) x 6,5 ]- [1/2 . 4,6 . 6,5]
= 40,95 - 14,95
= 26 cm2
luas belah ketupat
= 2 x 26
= 52 cm2
luas = 1/2 . d1 . d2
52 = 1/2 . 14,2 . d2
52 = 7,1 . d2
d2 = 7,3
maka panjang FH = 7,3 cm