Question

Jawab plis!!!
1. 3 * 2^x+1 - 4^x - 8 = 0
2. 4(16)^x - 17(4)^x + 4 = 0

Answer 1

1,,,,            3 (2)^(x+1) - (4)^x - 8 = 0 3. 2^x .2 - (2^x)^2 - 8 = 0 6 . 2^x - (2^x)^2 - 8 = 0 misal 2^x = a 6 (a) - (a)^2 - 8 = 0 a^2 - 6a + 8 = 0 (a-4)(a+2) = 0 a = 4 atau a = -2 2^x = a a = 4 --> 2^x = 4 --> x = 2 a = -2 --> 2^x = -a (TM) nilai x = 2

2),,,,,,,,,,,    4 (4^2)^x - 17(4^) + 4 = 0 4 (4^x)^2 - 17(4^x) + 4= 0 misal 4^x = a 4 a^2 - 17 a + 4= 0 (4a -1)(a-4) = 0 a = 1/4 atau a = 4 .. 4^x = a a= 1/4 --> 4^x = 1/4 = 4^-1 --> x = -1 a= 4 -----> 4^x = 4 ----> x = 1 HP ( x) = (1, -1)