V = ⅓πr²t
= ⅓.22/7.(7)².24
= 8.(22.7)
= 8.(154)
= 1.232 cm³
S = √r² + t²
= √7² + 24²
= √49 + 576
= √625
= 25cm
Lp = πr(r + s)
= 22/7.(7)(7 + 25)
= 22(32)
= 704cm²
maka V = 1.232cm³,L = 704cm²[C]
• Volume Kerucut :
_____ _
• cari garis pelukis terlebih dahulu (s) :
s = 7² + 24²
s = 49 + 576
s = 625 akar kuadrat pangkat 2
s = 25
• Luas Permukaan Kerucut :
Jadi, Jawabannya adalah (C.)
_________
~silah1234
" Life is not a problem to be solved but a reality to be experienced! "
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~Jawaban
V = ⅓πr²t
= ⅓.22/7.(7)².24
= 8.(22.7)
= 8.(154)
= 1.232 cm³
S = √r² + t²
= √7² + 24²
= √49 + 576
= √625
= 25cm
Lp = πr(r + s)
= 22/7.(7)(7 + 25)
= 22(32)
= 704cm²
maka V = 1.232cm³,L = 704cm²[C]
- Penyelesaian -
• Volume Kerucut :
_____ _
• cari garis pelukis terlebih dahulu (s) :
s = 7² + 24²
s = 49 + 576
s = 625 akar kuadrat pangkat 2
s = 25
_____ _
• Luas Permukaan Kerucut :
Jadi, Jawabannya adalah (C.)
_________
~silah1234