Luas permukaan balok
[tex]2(p \times l + p \times t + l \times t) \\ 2(25 \times 20 + 25 \times 20 + 20 \times 20) \\ 2(500 + 500 + 400) \\ 2(1.400) \\ 2.800 \: {cm}^{2} \\ \\ volume \: prisma \: segitiga \\ \frac{1}{2} \times alas \times t \: ∆ \times t \: prisma \\ \frac{1}{2} \times 3 \: cm \times 4 \: cm \times 10 \: cm \\ 60 \: {cm}^{3} [/tex]
LP :
= 2(25(20) + (25(20) + (20(20)
= 2(500 + 500 + 400)
= 2(1.000 + 400)
= 2(1.400)
= 2.800 CM²
V :
= 1/2(3(4(10)
= 1/2(3(40)
= 1/2(120)
= 120/2
= 60 CM³
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Verified answer
Luas permukaan balok
[tex]2(p \times l + p \times t + l \times t) \\ 2(25 \times 20 + 25 \times 20 + 20 \times 20) \\ 2(500 + 500 + 400) \\ 2(1.400) \\ 2.800 \: {cm}^{2} \\ \\ volume \: prisma \: segitiga \\ \frac{1}{2} \times alas \times t \: ∆ \times t \: prisma \\ \frac{1}{2} \times 3 \: cm \times 4 \: cm \times 10 \: cm \\ 60 \: {cm}^{3} [/tex]
LP :
= 2(25(20) + (25(20) + (20(20)
= 2(500 + 500 + 400)
= 2(1.000 + 400)
= 2(1.400)
= 2.800 CM²
V :
= 1/2(3(4(10)
= 1/2(3(40)
= 1/2(120)
= 120/2
= 60 CM³