∠B9 = ∠A4 + ∠A5
∠A3 + ∠B9 = 180°
(2x - 24)° + (3x + 19)° = 180
5x - 5 = 180
5x = 185
x = 37
∠A3 = 2(37) - 24 = 74 - 24 = 50°
∠B9 = 3(37) + 19 = 111 + 19 = 130°
∠A6 bertolak belakang dengan ∠A3
∠A6 = ∠A3 = 50°
∠B10 = 180° - ∠B9 = 180 - 130 = 50°
∠A5 merupakan penyiku ∠A6
∠A5 = 90° - 50° = 40°
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Verified answer
∠B9 = ∠A4 + ∠A5
∠A3 + ∠B9 = 180°
(2x - 24)° + (3x + 19)° = 180
5x - 5 = 180
5x = 185
x = 37
∠A3 = 2(37) - 24 = 74 - 24 = 50°
∠B9 = 3(37) + 19 = 111 + 19 = 130°
∠A6 bertolak belakang dengan ∠A3
∠A6 = ∠A3 = 50°
∠B10 = 180° - ∠B9 = 180 - 130 = 50°
∠A5 merupakan penyiku ∠A6
∠A5 = 90° - 50° = 40°