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Kelas 8 MatematikaBab Persamaan Garis
(0, 2) dan (3, 4)
(y - y1) / (y2 - y1) = (x - x1) / (x2 - x1)
(y - 2) / (4 - 2) = (x - 0) / (3 - 0)
(y - 2)/2 = x/3
y - 2 = 2x/3
y = (2/3) x + 2
f(x) = (2/3) x + 2
Verified answer
Titik potong = (0,2) dan (3,4)(y-y1)/(y2-y1) = (x-x1)/(x2-x1)
(y-2)/(4-2) = (x-0)/(3-0)
(y-2)/2 = x/3
y-2 =2/3 x
y = 2/3 x + 2
Jawabannya C. f(x) = 2/3 x + 2