Question

Jawab dengan caranya ya:3 yg dilingkari saja

Answer 1

1)
(2a^5 b / 16a²b^4)^-1
= 1/(2a^5 b / 16a²b^4)
= 1 x 16a²b^4 / 2a^5 b
= (16:2) a^2-5 b^4-1
= 8a^-3 b^3
= 8b^3 / a^3
= (2b / a)^3 ... (A)


4)
f(x) = 4 (1/3)^2-x
maka,
f(4)
= 4 (1/3)^2-4
= 4 (1/3)^-2
= 4 (1/(1/3)²)
= 4 (1/(1/9))
= 4.1.9/1
= 36 ... (A)