Penjelasan dengan langkah-langkah:
- s/ garis pelukis kerucut
= √r²+t²
= √6² +8²
= √36 + 64
= √100
= 10 cm
= 3,14.6.10
= 31,4.6
= 188,4 cm²
= πr ¾ (r + s)
= 3,14. 6 (6 + 10)
= 3,14.6.16
= 18,84.16
= 301,44 cm²
= π r² t
= 3.3,14.6.6.8
= 3,14.2.6.8
= 6,28.6.8
= 37,68.89
=301,44 cm³
semoga bermanfaat........
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Penjelasan dengan langkah-langkah:
DIKETAHUI=alas kerucut 6 cm jika tinggi kerucut 8 cm
DITANYA?
luas alas
B)luas selimut kerucut
C)luas permukaan kerucut.
PENYELESAIAN⏩
- s/ garis pelukis kerucut
= √r²+t²
= √6² +8²
= √36 + 64
= √100
= 10 cm
a. L. selimut kerucut
= 3,14.6.10
= 31,4.6
= 188,4 cm²
b. Lp kerucut
= πr ¾ (r + s)
= 3,14. 6 (6 + 10)
= 3,14.6.16
= 18,84.16
= 301,44 cm²
c. V. kerucut
= π r² t
= 3.3,14.6.6.8
= 3,14.2.6.8
= 6,28.6.8
= 37,68.89
=301,44 cm³
MAAF KALAU SALAH :)
SEMOGA BERMAMFAAT^^
TINGKATKAN PRESTASI MU✍
semoga bermanfaat........