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s²= √12²+3,5²
s²=√144+12,5
s²=√156,25
s= 12,5 cm
Luas Permukaan =>
phi x r (r+s)
3,14 x 3,5(3,5+12,5)
3,14 x 3,5(16)
3,14 x 56
175,84
Jadi Luas permukaan kerucut=> 175,84 cm ²