Diket
j=13 cm
R2=2cm
l=12 cm
ditanay R1..??
l=√j²-(r1-r2)²
12=√13²-(R1-2)²
144=169-(R1-2)²
(R1-2)²=169-144
(R1-2)²=25
(R1-2)=√25
(R1-2)=5
R1=5+2
R1=7 cm
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Diket
j=13 cm
R2=2cm
l=12 cm
ditanay R1..??
l=√j²-(r1-r2)²
12=√13²-(R1-2)²
144=169-(R1-2)²
(R1-2)²=169-144
(R1-2)²=25
(R1-2)=√25
(R1-2)=5
R1=5+2
R1=7 cm