diketahui :
jarak dua pusat lingkaran (p) = 17 cm
garis singgung persekutuan dalam (d) = 15 cm
jari " salah satu lingkaran = 3 cm
penyelesaian :
(R + r )² = p² - d²
(3 + r )² = 17² - 15²
(3 + r )² = 289 - 225
(3 + r )² = 64
(3 + r ) = akar 64
3 + r = 8 cm
r = 8 cm - 3 cm
r = 5 cm
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diketahui :
jarak dua pusat lingkaran (p) = 17 cm
garis singgung persekutuan dalam (d) = 15 cm
jari " salah satu lingkaran = 3 cm
penyelesaian :
(R + r )² = p² - d²
(3 + r )² = 17² - 15²
(3 + r )² = 289 - 225
(3 + r )² = 64
(3 + r ) = akar 64
3 + r = 8 cm
r = 8 cm - 3 cm
r = 5 cm