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5 4 4
6 7 11 ----> letak Q1
7 8 19 -----> letak Q3
8 3 21
9 1 23
n = 23
Letak quartil 1 = X1/4(n+1)
= X1/4(n+1)
= X1/4(23+1)
= X1/4(24)
= X6
karna letak Q1 di Xke6 maka nilai Q1 = 6
letak Q3 = X3/4(n+1)
= X3/4(23+1)
= X3/4(24)
= X18
karna letak Q3 di Xke18 maka nilai Q3 = 7
Jangkauan inter kuartil = Q3 -Q1 = 7 - 6 = 1