AC : CB = 2 : 1
AC = 2 × CB
C – A = 2 × (B – C)
C – A = 2B – 2C
2C + C = A + 2B
3C = A + 2B
C =
AC : CB = 3 : –2
3 × AC = –2 × CB
3 × (C – A) = –2 × (B – C)
3C – 3A = –2B + 2C
3C – 2C = 3A – 2B
C = 3A – 2B = =
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AC : CB = 2 : 1
AC = 2 × CB
C – A = 2 × (B – C)
C – A = 2B – 2C
2C + C = A + 2B
3C = A + 2B
C =
AC : CB = 3 : –2
3 × AC = –2 × CB
3 × (C – A) = –2 × (B – C)
3C – 3A = –2B + 2C
3C – 2C = 3A – 2B
C = 3A – 2B = =