Question

Tolong dijawab ya.. soalnya buat besok pagi

c.113 °F=..... °R
=..... °K
d.18 m/detik=..... km/jam

Answer 1

1.
113'F = ..... 'R
= 4/9 (tF - 32)
= 4/9 ( 113 - 32 )
= 4/9 x 81
= 36'R
,
2.
18 m/s = ..... km/jam
karena 1 m = 1/1000 km
1 s = 1/3600 jam
maka:
= (18 x 1/1000 km) / (1x 1/3600 jam)
= (18/1000 km) / (1/3600 jam)
= 18/1000km x 3600 jam
= (18x3600)/1000
= 64,8 km/jam

Answer 2

C.) 113'F = ..... 'R
     = 4/9 (tF - 32)
     = 4/9 ( 113 - 32 )
     = 4/9 x 81
     = 36`R

d.)18 m/s = ..... km/jam
karena 1 m = 1/1000 km
1 s = 1/3600 jam
maka:
= (18 x 1/1000 km) / (1x 1/3600 jam)
= (18/1000 km) / (1/3600 jam)
= 18/1000km x 3600 jam
= (18x3600)/1000
= 64,8 km/jam