Question

jalan yang bisa pintar nomor 1 sampai nomor 5 dengan caranya lengkap tapi pertanyaan ini khusus yang namanya kak syubbna

Answer 1

No 1)
a) y/2x - 2y/3x 
   = 3y/6x - 4y/6x
   = -y/6x

b) 3a/2b - a/3b
   = 9a/6b - 2a/6b
   = 7a/6b
  
c) (x+1)/6x + (x-2)/3x
    = (x+1)/6x + (2x-4)/6x
    = (3x-3)/6x
    = (x-1)/2x

d) 3x/y + (x^2+x)/xy
= 3x/y + (x+1)/y
= (4x+1)/y

no 2)
a) (3x/y)(x/2y) = (3x^2/y^2)
b) 9ab/6c x 6cb^2/3a^2 = 3b^3/a
c) (2x/3y) : (x/2y) = (2x/3y) x (2y/x)
     = 4xy/3xy
     = 4/3
d) (2a/b) : (2b/3a) = (2a/b) x (3a/2b)
    = 6a^2/2b^2
    = 3a^2/b^2

no 3)
a) (ab/2)^2 x (a/3b)^3
= (a^2b^2 / 4) x (a^3 / 27b^3)
= a^5b^2 / 108b^3
= a^5/108b

b) (3p/3q)^3 x (6q/p)^2
= (p^3/q^3) x (36q^2/p^2
= 36p^3q^2 / p^2q^3
= 36p/q

c) (3a/4b)^3 = 27a^3/64b^3

no 4) 
a) 2ab(3a - 5ab +6b) = 6a^2b - 10a^2b^2 + 12 ab^2
b) (3x-4)(2x-2) = 6x^2 - 14x + 8
c) (8x+13y)^2 = 64x^2 + 208xy + 169y^2
d) (3a^2 + 1/2)^2 = 9a^4 + 3a^2 + 1/4

no 5) 
a) 2x^2/xy x x^2y/xy = 2x^4y / x^2y^2
    = 2x^2/y

b) (6ab^2/ cd x c^2d/cd) : 6c/12a^2b
    = 6ab^2c^2d / c^2d^2  x  12a^2b/6c
   = 6ab^2/d  x 2a^2b / c
   = 12a^3b^3 / cd

diteliti lagi yaa , ... mudah"an faham