Jakie są wskazania woltomierza jeżeli opór wynosi 200Ω a natężenie 90mA
R=200Ω
I=90mA=0,009A
200Ω = U / 90 mA
U = 200Ω * 0,009 A
U = 1,8 V
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R=200Ω
I=90mA=0,009A
200Ω = U / 90 mA
U = 200Ω * 0,009 A
U = 1,8 V