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MgCl2 + 60 H2O
M MgCl2 = 95g/mol
M H2O = 18g/mol
18g/mol * 60 = 1080g
Cp = ms/mr*100%
mr = ms + m wody
mr = 95g + 1080g
mr = 1175g
Cp = 95g/1175g*100%
Cp = około 8,1%
Odp: Stężenie procentowe wynosi około 8,1%. ;)