jaki przyrost prędkosciu uzyska cialo o masie 2 kg, jezeli dziala na niego sila o wartosci 0,5 N w czasie 10 sekund ?
Dane: m = 2kg F = o,5 t = 10 F = m*a a=F/m a=0,5N/2kg = 1m/s^2 delta v=at delta v =1m/s^2 * 10s = 10 m/s
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Dane:
m = 2kg
F = o,5
t = 10
F = m*a
a=F/m
a=0,5N/2kg = 1m/s^2
delta v=at
delta v =1m/s^2 * 10s = 10 m/s