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M C12H22O11 = 342 g/mol
m = 10g
n = m/M = 10/342 = 0,029 mol
M H2O = 18g/mol
m = 90g
n = m/M = 90/18 = 5mol
1-----0,029
x-----5 x=172
Stosunek liczby cząstek sacharozy do wody ma się jak 1 : 172