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2·22.4 dm³ 3·22.4 dm³
2H2S + 3O2 → 2H2O + 2SO2
20 ml x
x = 30 ml tlenu - H2S jest nadmiar.
3·22.4 dm³ 2·22.4 dm³
2H2S + 3O2 →2 H2O + 2SO2
15 ml x
x = 10 ml SO2
proszę :)