jaka obietosc w warunkach normalnych zajmuje 4g amoniaku NH3
mNH3=17u
17g NH3------22,4dm3
4g NH3--------xdm3
x = 5,27dm3
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mNH3=17u
17g NH3------22,4dm3
4g NH3--------xdm3
x = 5,27dm3