Question

Jak to obliczyc?? Tylko c)
Dam naj:))))))))

Answer 1

Odpowiedź:

2*( sin³α + cos²α *sinα ) = 1

2*( sin³α + ( 1 - sin²α)*sin α ) = 1

2*( sin³α + sin α - sin³α ) = 1

2 sin α = 1  / : 2

sin α = 0,5

α = 30°

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Szczegółowe wyjaśnienie:

sin²α + cos²α = 1   ⇒  cos²α = 1 - sin²α

Answer 2

Verified answer

[tex]\huge\boxed{\alpha = 30^{o}}[/tex]

[tex]2(sin^3\alpha + cos^{2}\alpha\cdot sin \ \alpha) = 1\\\\2\cdot sin \ \alpha(sin^{2}\alpha + cos^{2}\alpha) = 1[/tex]

              sin²α + cos²α = 1

[tex]2sin \ \alpha \cdot 1 = 1\\\\2sin \ \alpha = 1 \ \ \ /:2\\\\sin \ \alpha = \frac{1}{2}\\\\\boxed{\alpha = 30^{o}}[/tex]