Jaką objętość zajmują dwa mole aronu pod ciśnieniem 200h Pa i w temperaturze 400 kelwinów.
n=2mole
p=200hPa
T=400K
R=83,1hPa*dm3/mol*K
pV=nRT
v=nRT/p
v=2*83,1*400/200
v = 332,4dm3
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n=2mole
p=200hPa
T=400K
R=83,1hPa*dm3/mol*K
pV=nRT
v=nRT/p
v=2*83,1*400/200
v = 332,4dm3