Jaką ilość moli stanowi 0,25 mg Ca(No3)2. Prosze z rozwiazaniem
1g=1000mg
M Ca(NO3)2=164g/mol
164000mg Ca(NO3)2------1mol
0,25mg Ca(NO3)2----------xmoli
x = 1,52*10^-6 mola
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1g=1000mg
M Ca(NO3)2=164g/mol
164000mg Ca(NO3)2------1mol
0,25mg Ca(NO3)2----------xmoli
x = 1,52*10^-6 mola