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Q1 = 2100 x 2 x 10
Q1 = 42000 J
Q2 = L m
Q2 = 335 000 x 2
Q2 = 700 000 J
Q3 = cm t
Q3 = 4200 x 2 x 50
Q3 = 420 000 J
Q = Q1 +Q2 + Q3
Q = 42 000 + 700 000 + 420 000 = 1162 000 J -- tyle trzeba dostarczyc ciepla
Q1 - ogrzewanie lodu do temp topnienia
Q2 - topnienie lodu
Q3 ogrzewanie wody do 50 C