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2. a. (Bilok N x 2) + (biloks O x 3) = 0
(2N) + (-2 x 3) = 0
2N -6 = 0
2N = 6 ==>N = 3 (biloks O = -2, N = +3)
b. (Na x 1) + (N x 1) + (O x 3) = 0
(1 x 1) + N + (-2 x 3) = 0
1 + N - 6 = 0
N - 5 = 0 ==> N = 5 (biloks N = +5, Na = +1, O = -2)
c. (k x 2) + (Cr x 2) + (O x 7) = 0
(1 x 2) + 2Cr + (-2 x 7) = 0
2 + 2Cr - 14 = 0
2Cr -12 = 0
2Cr = 12 ==> Cr = 6 (biloks Cr = +6, K = +1, O = -2)
d. (Cr x 1) + (O x 4) = -2
Cr + (-2 x 4) = -2
Cr -8 = -2
Cr = -2 + 8 ==> Cr = +6 (biloks Cr = +6, O = -2
d. (P x 1) + (O x 4) = -3
P + (-2 x 4) = -3
P -8 = -3
P = -3 +8
P = +5 (Biloks P = +5, O = -2)