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![p= \left[\begin{array}{cc}3&2\\3&4\end{array}\right] \\ invers: \\ \ p^{-1}= \frac{1}{det} . adj(p) \\ p^{-1}= \frac{1}{3.4-3.2} . \left[\begin{array}{cc}4&-2\\-3&3\end{array}\right] \\ p^{-1}= \frac{1}{12-6} . \left[\begin{array}{cc}4&-2\\-3&3\end{array}\right] \\ p^{-1}= \frac{1}{6} . \left[\begin{array}{cc}4&-2\\-3&3\end{array}\right] \\ p^{-1}= \left[\begin{array}{cc} \frac{4}{6} &\frac{-2}{6}\\\frac{-3}{6}&\frac{3}{6}\end{array}\right]](https://tex.z-dn.net/?f=p%3D++%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D3%262%5C%5C3%264%5Cend%7Barray%7D%5Cright%5D+++%5C%5C+invers%3A+%5C%5C++%5C+p%5E%7B-1%7D%3D++%5Cfrac%7B1%7D%7Bdet%7D+.+adj%28p%29+%5C%5C++p%5E%7B-1%7D%3D++%5Cfrac%7B1%7D%7B3.4-3.2%7D+.++%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D4%26-2%5C%5C-3%263%5Cend%7Barray%7D%5Cright%5D++%5C%5C+p%5E%7B-1%7D%3D++%5Cfrac%7B1%7D%7B12-6%7D+.++%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D4%26-2%5C%5C-3%263%5Cend%7Barray%7D%5Cright%5D++%5C%5C+p%5E%7B-1%7D%3D++%5Cfrac%7B1%7D%7B6%7D+.++%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D4%26-2%5C%5C-3%263%5Cend%7Barray%7D%5Cright%5D++%5C%5C+p%5E%7B-1%7D%3D++++%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D+%5Cfrac%7B4%7D%7B6%7D+%26%5Cfrac%7B-2%7D%7B6%7D%5C%5C%5Cfrac%7B-3%7D%7B6%7D%26%5Cfrac%7B3%7D%7B6%7D%5Cend%7Barray%7D%5Cright%5D+ "p= \left[\begin{array}{cc}3&2\\3&4\end{array}\right] \\ invers: \\ \ p^{-1}= \frac{1}{det} . adj(p) \\ p^{-1}= \frac{1}{3.4-3.2} . \left[\begin{array}{cc}4&-2\\-3&3\end{array}\right] \\ p^{-1}= \frac{1}{12-6} . \left[\begin{array}{cc}4&-2\\-3&3\end{array}\right] \\ p^{-1}= \frac{1}{6} . \left[\begin{array}{cc}4&-2\\-3&3\end{array}\right] \\ p^{-1}= \left[\begin{array}{cc} \frac{4}{6} &\frac{-2}{6}\\\frac{-3}{6}&\frac{3}{6}\end{array}\right]")
![p^{-1}= \left[\begin{array}{cc} \frac{2}{3} &\frac{-1}{3}\\\frac{-1}{2}&\frac{1}{2}\end{array}\right]](https://tex.z-dn.net/?f=p%5E%7B-1%7D%3D++++%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D+%5Cfrac%7B2%7D%7B3%7D+%26%5Cfrac%7B-1%7D%7B3%7D%5C%5C%5Cfrac%7B-1%7D%7B2%7D%26%5Cfrac%7B1%7D%7B2%7D%5Cend%7Barray%7D%5Cright%5D "p^{-1}= \left[\begin{array}{cc} \frac{2}{3} &\frac{-1}{3}\\\frac{-1}{2}&\frac{1}{2}\end{array}\right]")