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Verified answer
Agar parabola terletak diatas sumbu x, maka pers. y = (p-2)x² - 2px + (a+6) haruslah definit positif.y = (p-2)x² - 2px + (p+6)
a = (p - 2)
b = -2p
c = p+6
syarat definit positif
a > 0 dan D < 0
a > 0
p - 2 > 0
p > 2
D < 0
b² - 4ac < 0
(-2p)² - 4(p - 2)(p + 6) < 0
4p² - 4(p² + 4p - 12) < 0
4p² - 4p² - 16p + 48 < 0
-16p + 48 < 0
16p > 48
p > 3
irisan datri kedua syarat adalah p > 3
jadi batas-batas nilai p adlah p > 3